JEE MAIN - Physics (2022 - 29th June Evening Shift - No. 15)
A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of 'a' will be
$${g \over 4}$$
$${g \over 2}$$
$${3g \over 4}$$
g
توضیح
_29th_June_Evening_Shift_en_15_1.png)
Using Newton's second law
$$mg - {{mg} \over 4} = ma$$
$$ \Rightarrow a = {{3g} \over 4}$$